Input Methods for Exert

Devanagari

Exert uses the Itrans method. The following links may be useful:

Greek

Exert follows the greek-ibycus4 method supported by Emacs minus some cases Exert doesn't currently handle. After removing the cases Exert doesn't handle, the table of conversion is:

Sequence Result
(
) ᾿
=
A Α
B Β
C Ξ
D Δ
E Ε
F Φ
G Γ
H Η
I Ι
K Κ
L Λ
M Μ
N Ν
O Ο
P Π
Q Θ
R Ρ
S Σ
T Τ
U Υ
V Ϝ
W Ω
X Χ
Y Ψ
Z Ζ
a α
b β
c ξ
d δ
e ε
f φ
g γ
h η
i ι
j ς
k κ
l λ
m μ
n ν
o ο
p π
q θ
r ρ
s σ
t τ
u υ
v ϝ
w ω
x χ
y ψ
z ζ
| ͺ
'A
'E
'H
'I
'O
'U
'W
('
(=
(A
(E
(H
(I
(O
(U
(W
(`
)'
)=
)A
)E
)H
)I
)O
)W
)`
`A
`E
`H
`I
`O
`R
`U
`W
a'
a(
a)
a=
a`
a|
e'
e(
e)
e`
h'
h(
h)
h=
h`
h|
i'
i(
i)
i=
i`
o'
o(
o)
o`
r(
r)
u'
u(
u)
u=
u`
w'
w(
w)
w=
w`
w|
('A
('E
('H
('I
('O
('U
('W
(=A
(=H
(=I Ἷ
(=U
(=W
(`A
(`E
(`H
(`I
(`O
(`U
(`W
)'A
)'E
)'H
)'I
)'O
)'W
)=A
)=H
)=I
)=W
)Ai
)Hi
)Wi
)`A
)`E
)`H
)`I
)`O
)`W
a'|
a('
a(=
a(`
a(|
a)'
a)=
a)`
a)|
a=|
a`|
e('
e(`
e)'
e)`
h'|
h('
h(=
h(`
h(|
h)'
h)=
h)`
h)|
h=|
h`|
i('
i(=
i(`
i)'
i)=
i)`
o('
o(`
o)'
o)`
u('
u(=
u(`
u)'
u)=
u)`
w'|
w('
w(=
w(`
w(|
w)'
w)=
w)`
w)|
w=|
w`|
a('|
a(=|
a(`|
a)'|
a)=|
a)`|
h('|
h(=|
h(`|
h)'|
h)=|
h)`|
w('|
w(=|
w(`|
w)'|
w)=|
w)`|